C 语言实例 - 计算两个时间段的差值 C 语言实例 C 语言实例计算两个时间段的差值。实例#include 
     
       struct TIME{  int seconds;  int minutes;  int hours;};void differenceBetweenTimePeriod(struct TIME t1, struct TIME t2, struct TIME *diff); int main(){    struct TIME startTime, stopTime, diff;     printf("输入开始时间: \n");    printf("输入小时、分钟、秒：");    scanf("%d %d %d", &startTime.hours, &startTime.minutes, &startTime.seconds);     printf("输入停止时间: \n");    printf("输入小时、分钟、秒: ");    scanf("%d %d %d", &stopTime.hours, &stopTime.minutes, &stopTime.seconds);     // 计算差值    differenceBetweenTimePeriod(startTime, stopTime, &diff);     printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds);    printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds);    printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds);     return 0;} void differenceBetweenTimePeriod(struct TIME start, struct TIME stop, struct TIME *diff){    if(stop.seconds > start.seconds){        --start.minutes;        start.seconds += 60;    }     diff->seconds = start.seconds - stop.seconds;    if(stop.minutes > start.minutes){        --start.hours;        start.minutes += 60;    }     diff->minutes = start.minutes - stop.minutes;    diff->hours = start.hours - stop.hours;}输出结果为：输入开始时间: 输入小时、分钟、秒：12 34 55输入停止时间: 输入小时、分钟、秒: 8 12 5差值: 12:34:55 - 8:12:5 = 4:22:50